Cos (A/2) given Sides B and C and Sin (A/2) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2))
cos(A/2) = A/(Sb*Sc*sin(A/2))
This formula uses 5 Variables
Variables Used
Cos (A/2) - Cos (A/2) is the value of the trigonometric cosine function of half of the given angle A of the triangle.
Area of Triangle - (Measured in Square Meter) - The Area of Triangle is the amount of region or space occupied by the Triangle.
Side B of Triangle - (Measured in Meter) - The Side B of Triangle is the length of the side B of the three sides. In other words, the side Bof the Triangle is the side opposite to the angle B.
Side C of Triangle - (Measured in Meter) - The Side C of Triangle is the length of the side C of the three sides. In other words, side C of the Triangle is the side opposite to angle C.
Sin (A/2) - Sin (A/2) is the value of the trigonometric sine function of half of the given angle A of the triangle.
STEP 1: Convert Input(s) to Base Unit
Area of Triangle: 65 Square Meter --> 65 Square Meter No Conversion Required
Side B of Triangle: 14 Meter --> 14 Meter No Conversion Required
Side C of Triangle: 20 Meter --> 20 Meter No Conversion Required
Sin (A/2): 0.25 --> No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
cos(A/2) = A/(Sb*Sc*sin(A/2)) --> 65/(14*20*0.25)
Evaluating ... ...
cos(A/2) = 0.928571428571429
STEP 3: Convert Result to Output's Unit
0.928571428571429 --> No Conversion Required
FINAL ANSWER
0.928571428571429 0.928571 <-- Cos (A/2)
(Calculation completed in 00.004 seconds)

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Created by Surjojoti Som
Rashtreeya Vidyalaya College of Engineering (RVCE), Bangalore
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Trigonometric Ratios of Half Angles using Area of the Triangle Calculators

Sin (A/2) given Sides B and C and Cos (A/2)
​ LaTeX ​ Go Sin (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Cos (A/2))
Sin (B/2) given Sides A and C and Cos (B/2)
​ LaTeX ​ Go Sin (B/2) = Area of Triangle/(Side A of Triangle*Side C of Triangle*Cos (B/2))
Sin (C/2) given Sides A and B and Cos (C/2)
​ LaTeX ​ Go Sin (C/2) = Area of Triangle/(Side A of Triangle*Side B of Triangle*Cos (C/2))
Cos (A/2) given Sides B and C and Sin (A/2)
​ LaTeX ​ Go Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2))

Cos (A/2) given Sides B and C and Sin (A/2) Formula

​LaTeX ​Go
Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2))
cos(A/2) = A/(Sb*Sc*sin(A/2))

What is a Triangle?

The Triangle is the type of polygon, which have three sides and three vertices. This is a two-dimensional figure with three straight sides. A triangle is considered a 3-sided polygon. The sum of all the three angles of a triangle is equal to 180°. The triangle is contained in a single plane. Based on its sides and angle measurement, the triangle has six types.

How to Calculate Cos (A/2) given Sides B and C and Sin (A/2)?

Cos (A/2) given Sides B and C and Sin (A/2) calculator uses Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2)) to calculate the Cos (A/2), The Cos (A/2) given Sides B and C and Sin (A/2) formula is defined as value of cos A/2 using area of the triangle, the sides B & C and the trigonometric half ratio Sin A/2. Cos (A/2) is denoted by cos(A/2) symbol.

How to calculate Cos (A/2) given Sides B and C and Sin (A/2) using this online calculator? To use this online calculator for Cos (A/2) given Sides B and C and Sin (A/2), enter Area of Triangle (A), Side B of Triangle (Sb), Side C of Triangle (Sc) & Sin (A/2) (sin(A/2)) and hit the calculate button. Here is how the Cos (A/2) given Sides B and C and Sin (A/2) calculation can be explained with given input values -> 0.928571 = 65/(14*20*0.25).

FAQ

What is Cos (A/2) given Sides B and C and Sin (A/2)?
The Cos (A/2) given Sides B and C and Sin (A/2) formula is defined as value of cos A/2 using area of the triangle, the sides B & C and the trigonometric half ratio Sin A/2 and is represented as cos(A/2) = A/(Sb*Sc*sin(A/2)) or Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2)). The Area of Triangle is the amount of region or space occupied by the Triangle, The Side B of Triangle is the length of the side B of the three sides. In other words, the side Bof the Triangle is the side opposite to the angle B, The Side C of Triangle is the length of the side C of the three sides. In other words, side C of the Triangle is the side opposite to angle C & Sin (A/2) is the value of the trigonometric sine function of half of the given angle A of the triangle.
How to calculate Cos (A/2) given Sides B and C and Sin (A/2)?
The Cos (A/2) given Sides B and C and Sin (A/2) formula is defined as value of cos A/2 using area of the triangle, the sides B & C and the trigonometric half ratio Sin A/2 is calculated using Cos (A/2) = Area of Triangle/(Side B of Triangle*Side C of Triangle*Sin (A/2)). To calculate Cos (A/2) given Sides B and C and Sin (A/2), you need Area of Triangle (A), Side B of Triangle (Sb), Side C of Triangle (Sc) & Sin (A/2) (sin(A/2)). With our tool, you need to enter the respective value for Area of Triangle, Side B of Triangle, Side C of Triangle & Sin (A/2) and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
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