Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Calculator

✖Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.ⓘ Cross-Sectional Area of Reservoir [A_R]			+10% -10%
✖Time interval is the time duration between two events/entities of interest.ⓘ Time Interval [Δt]			+10% -10%
✖The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.ⓘ Acceleration due to Gravity [g]			+10% -10%
✖Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.ⓘ Theta [θ]			+10% -10%
✖Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.ⓘ Head on Downstream of Weir [h₂]			+10% -10%
✖Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.ⓘ Head on Upstream of Weir [H_Upstream]			+10% -10%

✖The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.ⓘ Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch [C_d]

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Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Solution

STEP 0: Pre-Calculation Summary

Formula Used

Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2)))
C_d = (((2/3)*A_R)/((8/15)*Δt*sqrt(2*g)*tan(θ/2)))*((1/h₂^(3/2))-(1/H_Upstream^(3/2)))
This formula uses 2 Functions, 7 Variables

Functions Used

tan - The tangent of an angle is a trigonometric ratio of the length of the side opposite an angle to the length of the side adjacent to an angle in a right triangle., tan(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Coefficient of Discharge - The Coefficient of Discharge is ratio of actual discharge to theoretical discharge.
Cross-Sectional Area of Reservoir - (Measured in Square Meter) - Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point.
Time Interval - (Measured in Second) - Time interval is the time duration between two events/entities of interest.
Acceleration due to Gravity - (Measured in Meter per Square Second) - The Acceleration due to Gravity is acceleration gained by an object because of gravitational force.
Theta - (Measured in Radian) - Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint.
Head on Downstream of Weir - (Measured in Meter) - Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.
Head on Upstream of Weir - (Measured in Meter) - Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

STEP 1: Convert Input(s) to Base Unit

Cross-Sectional Area of Reservoir: 13 Square Meter --> 13 Square Meter No Conversion Required
Time Interval: 1.25 Second --> 1.25 Second No Conversion Required
Acceleration due to Gravity: 9.8 Meter per Square Second --> 9.8 Meter per Square Second No Conversion Required
Theta: 30 Degree --> 0.5235987755982 Radian (Check conversion here)
Head on Downstream of Weir: 5.1 Meter --> 5.1 Meter No Conversion Required
Head on Upstream of Weir: 10.1 Meter --> 10.1 Meter No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

C_d = (((2/3)*A_R)/((8/15)*Δt*sqrt(2*g)*tan(θ/2)))*((1/h₂^(3/2))-(1/H_Upstream^(3/2))) --> (((2/3)*13)/((8/15)*1.25*sqrt(2*9.8)*tan(0.5235987755982/2)))*((1/5.1^(3/2))-(1/10.1^(3/2)))

Evaluating ... ...

C_d = 0.610083797710571

STEP 3: Convert Result to Output's Unit

0.610083797710571 --> No Conversion Required

FINAL ANSWER

0.610083797710571 ≈ 0.610084 <-- Coefficient of Discharge

(Calculation completed in 00.004 seconds)

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< Time Required to Empty a Reservoir with Rectangular Weir Calculators

Coefficient of Discharge for Time Required to Lower Liquid Surface

LaTeX Go Coefficient of Discharge = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Time Interval*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Length of Crest for time required to Lower Liquid Surface

LaTeX Go Length of Weir Crest = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Time Interval))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Time Required to Lower Liquid Surface

LaTeX Go Time Interval = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

Cross Sectional Area given Time required to Lower Liquid Surface

LaTeX Go Cross-Sectional Area of Reservoir = (Time Interval*(2/3)*Coefficient of Discharge*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest)/(2*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir)))

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch Formula

LaTeX Go

What is Acceleration due to gravity?

Acceleration due to gravity defines the acceleration which is gained by an object because of gravitational force is called its acceleration due to gravity.

How to Calculate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch calculator uses Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))) to calculate the Coefficient of Discharge, The Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch is ratio of actual discharge to theoretical discharge, i.e., ratio of mass flow rate at discharge end. Coefficient of Discharge is denoted by C_d symbol.

How to calculate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch using this online calculator? To use this online calculator for Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch, enter Cross-Sectional Area of Reservoir (A_R), Time Interval (Δt), Acceleration due to Gravity (g), Theta (θ), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream) and hit the calculate button. Here is how the Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch calculation can be explained with given input values -> 0.610084 = (((2/3)*13)/((8/15)*1.25*sqrt(2*9.8)*tan(0.5235987755982/2)))*((1/5.1^(3/2))-(1/10.1^(3/2))).

FAQ

What is Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

The Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch is ratio of actual discharge to theoretical discharge, i.e., ratio of mass flow rate at discharge end and is represented as C_d = (((2/3)*A_R)/((8/15)*Δt*sqrt(2*g)*tan(θ/2)))*((1/h₂^(3/2))-(1/H_Upstream^(3/2))) or Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))). Cross-Sectional Area of Reservoir is the area of a reservoir that is obtained when a three-dimensional reservoir shape is sliced perpendicular to some specified axis at a point, Time interval is the time duration between two events/entities of interest, The Acceleration due to Gravity is acceleration gained by an object because of gravitational force, Theta is an angle that can be defined as the figure formed by two rays meeting at a common endpoint, Head on Downstream of Weir pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures & Head on Upstream of Weirr pertains to the energy status of water in water flow systems and is useful for describing flow in hydraulic structures.

How to calculate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch?

The Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch is ratio of actual discharge to theoretical discharge, i.e., ratio of mass flow rate at discharge end is calculated using Coefficient of Discharge = (((2/3)*Cross-Sectional Area of Reservoir)/((8/15)*Time Interval*sqrt(2*Acceleration due to Gravity)*tan(Theta/2)))*((1/Head on Downstream of Weir^(3/2))-(1/Head on Upstream of Weir^(3/2))). To calculate Coefficient of Discharge given Time required to Lower Liquid for Triangular Notch, you need Cross-Sectional Area of Reservoir (A_R), Time Interval (Δt), Acceleration due to Gravity (g), Theta (θ), Head on Downstream of Weir (h₂) & Head on Upstream of Weir (H_Upstream). With our tool, you need to enter the respective value for Cross-Sectional Area of Reservoir, Time Interval, Acceleration due to Gravity, Theta, Head on Downstream of Weir & Head on Upstream of Weir and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Coefficient of Discharge?

In this formula, Coefficient of Discharge uses Cross-Sectional Area of Reservoir, Time Interval, Acceleration due to Gravity, Theta, Head on Downstream of Weir & Head on Upstream of Weir. We can use 1 other way(s) to calculate the same, which is/are as follows -

Coefficient of Discharge = ((2*Cross-Sectional Area of Reservoir)/((2/3)*Time Interval*sqrt(2*Acceleration due to Gravity)*Length of Weir Crest))*(1/sqrt(Head on Downstream of Weir)-1/sqrt(Head on Upstream of Weir))

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