Clausius Parametera given Reduced and Critical Parameters using Clausius Equation Calculator

✖Reduced Molar Volume of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.ⓘ Reduced Molar Volume [V_m,r]			+10% -10%
✖Critical Temperature is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor.ⓘ Critical Temperature [T_c]			+10% -10%
✖Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole.ⓘ Critical Molar Volume [V_m,c]			+10% -10%
✖Clausius parameter b is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter b [b]			+10% -10%
✖Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.ⓘ Reduced Pressure [P_r]			+10% -10%
✖Critical Pressure is the minimum pressure required to liquify a substance at the critical temperature.ⓘ Critical Pressure [P_c]			+10% -10%
✖Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.ⓘ Reduced Temperature [T_r]			+10% -10%
✖Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parameter c [c]			+10% -10%

✖Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.ⓘ Clausius Parametera given Reduced and Critical Parameters using Clausius Equation [a]

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Clausius Parametera given Reduced and Critical Parameters using Clausius Equation Solution

STEP 0: Pre-Calculation Summary

Formula Used

Clausius Parameter a = ((([R]*(Reduced Molar Volume*Critical Temperature))/((Reduced Molar Volume*Critical Molar Volume)-Clausius Parameter b))-(Reduced Pressure*Critical Pressure))*((Reduced Temperature*Critical Temperature)*(((Reduced Molar Volume*Critical Molar Volume)+Clausius Parameter c)^2))
a = ((([R]*(V_m,r*T_c))/((V_m,r*V_m,c)-b))-(P_r*P_c))*((T_r*T_c)*(((V_m,r*V_m,c)+c)^2))
This formula uses 1 Constants, 9 Variables

Constants Used

[R] - Universal gas constant Value Taken As 8.31446261815324

Variables Used

Clausius Parameter a - Clausius parameter a is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Reduced Molar Volume - Reduced Molar Volume of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole.
Critical Temperature - (Measured in Kelvin) - Critical Temperature is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor.
Critical Molar Volume - (Measured in Cubic Meter per Mole) - Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole.
Clausius Parameter b - Clausius parameter b is an empirical parameter characteristic to equation obtained from Clausius model of real gas.
Reduced Pressure - Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless.
Critical Pressure - (Measured in Pascal) - Critical Pressure is the minimum pressure required to liquify a substance at the critical temperature.
Reduced Temperature - Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless.
Clausius Parameter c - Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

STEP 1: Convert Input(s) to Base Unit

Reduced Molar Volume: 11.2 --> No Conversion Required
Critical Temperature: 647 Kelvin --> 647 Kelvin No Conversion Required
Critical Molar Volume: 11.5 Cubic Meter per Mole --> 11.5 Cubic Meter per Mole No Conversion Required
Clausius Parameter b: 0.15 --> No Conversion Required
Reduced Pressure: 0.8 --> No Conversion Required
Critical Pressure: 218 Pascal --> 218 Pascal No Conversion Required
Reduced Temperature: 10 --> No Conversion Required
Clausius Parameter c: 0.0002 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

a = ((([R]*(V_m,r*T_c))/((V_m,r*V_m,c)-b))-(P_r*P_c))*((T_r*T_c)*(((V_m,r*V_m,c)+c)^2)) --> ((([R]*(11.2*647))/((11.2*11.5)-0.15))-(0.8*218))*((10*647)*(((11.2*11.5)+0.0002)^2))

Evaluating ... ...

a = 31548074396.715

STEP 3: Convert Result to Output's Unit

31548074396.715 --> No Conversion Required

FINAL ANSWER

31548074396.715 ≈ 3.2E+10 <-- Clausius Parameter a

(Calculation completed in 00.004 seconds)

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< Clausius Parameter Calculators

Clausius Parametera given Reduced and Critical Parameters using Clausius Equation

LaTeX Go Clausius Parameter a = ((([R]*(Reduced Molar Volume*Critical Temperature))/((Reduced Molar Volume*Critical Molar Volume)-Clausius Parameter b))-(Reduced Pressure*Critical Pressure))*((Reduced Temperature*Critical Temperature)*(((Reduced Molar Volume*Critical Molar Volume)+Clausius Parameter c)^2))

Clausius Parameter given Pressure, Temperature and Molar Volume of Real Gas

LaTeX Go Clausius Parameter a = ((([R]*Temperature of Real Gas)/(Molar Volume-Clausius Parameter b))-Pressure)*(Temperature of Real Gas*((Molar Volume+Clausius Parameter c)^2))

Clausius Parameter given Reduced and Actual Parameters

LaTeX Go Clausius Parameter a = (27*([R]^2)*((Temperature of Real Gas/Reduced Temperature)^3))/(64*(Pressure/Reduced Pressure))

Clausius Parameter given Critical Parameters

LaTeX Go Clausius Parameter a = (27*([R]^2)*(Critical Temperature^3))/(64*Critical Pressure)

Clausius Parametera given Reduced and Critical Parameters using Clausius Equation Formula

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What are Real Gases?

Real gases are non ideal gases whose molecules occupy space and have interactions; consequently, they do not adhere to the ideal gas law. To understand the behavior of real gases, the following must be taken into account:
- compressibility effects;
- variable specific heat capacity;
- van der Waals forces;
- non-equilibrium thermodynamic effects;
- issues with molecular dissociation and elementary reactions with variable composition.

How to Calculate Clausius Parametera given Reduced and Critical Parameters using Clausius Equation?

Clausius Parametera given Reduced and Critical Parameters using Clausius Equation calculator uses Clausius Parameter a = ((([R]*(Reduced Molar Volume*Critical Temperature))/((Reduced Molar Volume*Critical Molar Volume)-Clausius Parameter b))-(Reduced Pressure*Critical Pressure))*((Reduced Temperature*Critical Temperature)*(((Reduced Molar Volume*Critical Molar Volume)+Clausius Parameter c)^2)) to calculate the Clausius Parameter a, The Clausius parametera given reduced and critical parameters using Clausius equation formula is defined as an empirical parameter characteristic to equation obtained from Clausius model of real gas. Clausius Parameter a is denoted by a symbol.

How to calculate Clausius Parametera given Reduced and Critical Parameters using Clausius Equation using this online calculator? To use this online calculator for Clausius Parametera given Reduced and Critical Parameters using Clausius Equation, enter Reduced Molar Volume (V_m,r), Critical Temperature (T_c), Critical Molar Volume (V_m,c), Clausius Parameter b (b), Reduced Pressure (P_r), Critical Pressure (P_c), Reduced Temperature (T_r) & Clausius Parameter c (c) and hit the calculate button. Here is how the Clausius Parametera given Reduced and Critical Parameters using Clausius Equation calculation can be explained with given input values -> 3.2E+10 = ((([R]*(11.2*647))/((11.2*11.5)-0.15))-(0.8*218))*((10*647)*(((11.2*11.5)+0.0002)^2)).

FAQ

What is Clausius Parametera given Reduced and Critical Parameters using Clausius Equation?

The Clausius parametera given reduced and critical parameters using Clausius equation formula is defined as an empirical parameter characteristic to equation obtained from Clausius model of real gas and is represented as a = ((([R]*(V_m,r*T_c))/((V_m,r*V_m,c)-b))-(P_r*P_c))*((T_r*T_c)*(((V_m,r*V_m,c)+c)^2)) or Clausius Parameter a = ((([R]*(Reduced Molar Volume*Critical Temperature))/((Reduced Molar Volume*Critical Molar Volume)-Clausius Parameter b))-(Reduced Pressure*Critical Pressure))*((Reduced Temperature*Critical Temperature)*(((Reduced Molar Volume*Critical Molar Volume)+Clausius Parameter c)^2)). Reduced Molar Volume of a fluid is computed from the ideal gas law at the substance's critical pressure and temperature per mole, Critical Temperature is the highest temperature at which the substance can exist as a liquid. At this phase boundaries vanish, and the substance can exist both as a liquid and vapor, Critical Molar Volume is the volume occupied by gas at critical temperature and pressure per mole, Clausius parameter b is an empirical parameter characteristic to equation obtained from Clausius model of real gas, Reduced Pressure is the ratio of the actual pressure of the fluid to its critical pressure. It is dimensionless, Critical Pressure is the minimum pressure required to liquify a substance at the critical temperature, Reduced Temperature is the ratio of the actual temperature of the fluid to its critical temperature. It is dimensionless & Clausius parameter c is an empirical parameter characteristic to equation obtained from Clausius model of real gas.

How to calculate Clausius Parametera given Reduced and Critical Parameters using Clausius Equation?

The Clausius parametera given reduced and critical parameters using Clausius equation formula is defined as an empirical parameter characteristic to equation obtained from Clausius model of real gas is calculated using Clausius Parameter a = ((([R]*(Reduced Molar Volume*Critical Temperature))/((Reduced Molar Volume*Critical Molar Volume)-Clausius Parameter b))-(Reduced Pressure*Critical Pressure))*((Reduced Temperature*Critical Temperature)*(((Reduced Molar Volume*Critical Molar Volume)+Clausius Parameter c)^2)). To calculate Clausius Parametera given Reduced and Critical Parameters using Clausius Equation, you need Reduced Molar Volume (V_m,r), Critical Temperature (T_c), Critical Molar Volume (V_m,c), Clausius Parameter b (b), Reduced Pressure (P_r), Critical Pressure (P_c), Reduced Temperature (T_r) & Clausius Parameter c (c). With our tool, you need to enter the respective value for Reduced Molar Volume, Critical Temperature, Critical Molar Volume, Clausius Parameter b, Reduced Pressure, Critical Pressure, Reduced Temperature & Clausius Parameter c and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Clausius Parameter a?

In this formula, Clausius Parameter a uses Reduced Molar Volume, Critical Temperature, Critical Molar Volume, Clausius Parameter b, Reduced Pressure, Critical Pressure, Reduced Temperature & Clausius Parameter c. We can use 3 other way(s) to calculate the same, which is/are as follows -

Clausius Parameter a = (27*([R]^2)*(Critical Temperature^3))/(64*Critical Pressure)
Clausius Parameter a = ((([R]*Temperature of Real Gas)/(Molar Volume-Clausius Parameter b))-Pressure)*(Temperature of Real Gas*((Molar Volume+Clausius Parameter c)^2))
Clausius Parameter a = (27*([R]^2)*((Temperature of Real Gas/Reduced Temperature)^3))/(64*(Pressure/Reduced Pressure))

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