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C.O.P. of simple air evaporative cycle Calculator

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✖Tonnage of Refrigeration in TR is the unit of measurement for the cooling capacity of an air refrigeration system, typically used in industrial and commercial applications.ⓘ Tonnage of Refrigeration in TR [Q]			+10% -10%
✖Mass of Air is the amount of air present in a refrigeration system, which affects the cooling performance and overall efficiency of the system.ⓘ Mass of Air [ma]			+10% -10%
✖Specific Heat Capacity at Constant Pressure is the amount of heat required to change the temperature of air in refrigeration systems by one degree Celsius.ⓘ Specific Heat Capacity at Constant Pressure [C_p]			+10% -10%
✖Actual End Temp of Isentropic Compression is the final temperature of air at the end of an isentropic compression process in air refrigeration systems.ⓘ Actual End Temp of Isentropic Compression [Tt^']			+10% -10%
✖Actual temperature of Rammed Air is the temperature of air after it has been compressed and cooled in an air refrigeration system.ⓘ Actual Temperature of Rammed Air [T2^']			+10% -10%

✖Actual Coefficient of Performance is a measure of the effectiveness of an air refrigeration system in transferring heat from one location to another.ⓘ C.O.P. of simple air evaporative cycle [COP_actual]

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C.O.P. of simple air evaporative cycle Solution

STEP 0: Pre-Calculation Summary

Formula Used

Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air))
COP_actual = (210*Q)/(ma*C_p*(Tt^'-T2^'))
This formula uses 6 Variables

Variables Used

Actual Coefficient of Performance - Actual Coefficient of Performance is a measure of the effectiveness of an air refrigeration system in transferring heat from one location to another.
Tonnage of Refrigeration in TR - Tonnage of Refrigeration in TR is the unit of measurement for the cooling capacity of an air refrigeration system, typically used in industrial and commercial applications.
Mass of Air - (Measured in Kilogram per Second) - Mass of Air is the amount of air present in a refrigeration system, which affects the cooling performance and overall efficiency of the system.
Specific Heat Capacity at Constant Pressure - (Measured in Joule per Kilogram per K) - Specific Heat Capacity at Constant Pressure is the amount of heat required to change the temperature of air in refrigeration systems by one degree Celsius.
Actual End Temp of Isentropic Compression - (Measured in Kelvin) - Actual End Temp of Isentropic Compression is the final temperature of air at the end of an isentropic compression process in air refrigeration systems.
Actual Temperature of Rammed Air - (Measured in Kelvin) - Actual temperature of Rammed Air is the temperature of air after it has been compressed and cooled in an air refrigeration system.

STEP 1: Convert Input(s) to Base Unit

Tonnage of Refrigeration in TR: 150 --> No Conversion Required
Mass of Air: 120 Kilogram per Minute --> 2 Kilogram per Second (Check conversion here)
Specific Heat Capacity at Constant Pressure: 1.005 Kilojoule per Kilogram per K --> 1005 Joule per Kilogram per K (Check conversion here)
Actual End Temp of Isentropic Compression: 350 Kelvin --> 350 Kelvin No Conversion Required
Actual Temperature of Rammed Air: 273 Kelvin --> 273 Kelvin No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

COP_actual = (210*Q)/(ma*C_p*(Tt^'-T2^')) --> (210*150)/(2*1005*(350-273))

Evaluating ... ...

COP_actual = 0.203527815468114

STEP 3: Convert Result to Output's Unit

0.203527815468114 --> No Conversion Required

FINAL ANSWER

0.203527815468114 ≈ 0.203528 <-- Actual Coefficient of Performance

(Calculation completed in 00.004 seconds)

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Created by Rushi Shah

K J Somaiya College of Engineering (K J Somaiya), Mumbai

Rushi Shah has created this Calculator and 25+ more calculators!

Verified by Suman Ray Pramanik

Indian Institute of Technology (IIT), Kanpur

Suman Ray Pramanik has verified this Calculator and 100+ more calculators!

< Air Refrigeration Calculators

Compression or Expansion Ratio

LaTeX Go Compression or Expansion Ratio = Pressure at End of Isentropic Compression/Pressure at Start of Isentropic Compression

Relative Coefficient of Performance

LaTeX Go Relative Coefficient of Performance = Actual Coefficient of Performance/Theoretical Coefficient of Performance

Energy Performance Ratio of Heat Pump

LaTeX Go Theoretical Coefficient of Performance = Heat Delivered to Hot Body/Work Done per min

Theoretical Coefficient of Performance of Refrigerator

LaTeX Go Theoretical Coefficient of Performance = Heat Extracted from Refrigerator/Work Done

C.O.P. of simple air evaporative cycle Formula

LaTeX Go

What is Simple Air Evaporative Cycle?

The Simple Air Evaporative Cycle is a basic refrigeration process where air is used as the working fluid. In this cycle, air is compressed, cooled by removing heat, expanded to lower its temperature, and then used to absorb heat from the space to be cooled. This cycle is commonly used in aircraft refrigeration systems due to its simplicity and reliability.

How to Calculate C.O.P. of simple air evaporative cycle?

C.O.P. of simple air evaporative cycle calculator uses Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)) to calculate the Actual Coefficient of Performance, C.O.P. of simple air evaporative cycle formula is defined as a measure of the actual performance of an air evaporative cooling system, which indicates its ability to transfer heat from the air to the water, providing a cooling effect. It is a key parameter in evaluating the efficiency of air evaporative cooling systems. Actual Coefficient of Performance is denoted by COP_actual symbol.

How to calculate C.O.P. of simple air evaporative cycle using this online calculator? To use this online calculator for C.O.P. of simple air evaporative cycle, enter Tonnage of Refrigeration in TR (Q), Mass of Air (ma), Specific Heat Capacity at Constant Pressure (C_p), Actual End Temp of Isentropic Compression (Tt^') & Actual Temperature of Rammed Air (T2^') and hit the calculate button. Here is how the C.O.P. of simple air evaporative cycle calculation can be explained with given input values -> 0.244233 = (210*150)/(2*1005*(350-273)).

FAQ

What is C.O.P. of simple air evaporative cycle?

C.O.P. of simple air evaporative cycle formula is defined as a measure of the actual performance of an air evaporative cooling system, which indicates its ability to transfer heat from the air to the water, providing a cooling effect. It is a key parameter in evaluating the efficiency of air evaporative cooling systems and is represented as COP_actual = (210*Q)/(ma*C_p*(Tt^'-T2^')) or Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)). Tonnage of Refrigeration in TR is the unit of measurement for the cooling capacity of an air refrigeration system, typically used in industrial and commercial applications, Mass of Air is the amount of air present in a refrigeration system, which affects the cooling performance and overall efficiency of the system, Specific Heat Capacity at Constant Pressure is the amount of heat required to change the temperature of air in refrigeration systems by one degree Celsius, Actual End Temp of Isentropic Compression is the final temperature of air at the end of an isentropic compression process in air refrigeration systems & Actual temperature of Rammed Air is the temperature of air after it has been compressed and cooled in an air refrigeration system.

How to calculate C.O.P. of simple air evaporative cycle?

C.O.P. of simple air evaporative cycle formula is defined as a measure of the actual performance of an air evaporative cooling system, which indicates its ability to transfer heat from the air to the water, providing a cooling effect. It is a key parameter in evaluating the efficiency of air evaporative cooling systems is calculated using Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Mass of Air*Specific Heat Capacity at Constant Pressure*(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)). To calculate C.O.P. of simple air evaporative cycle, you need Tonnage of Refrigeration in TR (Q), Mass of Air (ma), Specific Heat Capacity at Constant Pressure (C_p), Actual End Temp of Isentropic Compression (Tt^') & Actual Temperature of Rammed Air (T2^'). With our tool, you need to enter the respective value for Tonnage of Refrigeration in TR, Mass of Air, Specific Heat Capacity at Constant Pressure, Actual End Temp of Isentropic Compression & Actual Temperature of Rammed Air and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Actual Coefficient of Performance?

In this formula, Actual Coefficient of Performance uses Tonnage of Refrigeration in TR, Mass of Air, Specific Heat Capacity at Constant Pressure, Actual End Temp of Isentropic Compression & Actual Temperature of Rammed Air. We can use 2 other way(s) to calculate the same, which is/are as follows -

Actual Coefficient of Performance = (Inside Temperature of Cabin-Actual Temperature at end of Isentropic Expansion)/(Actual End Temp of Isentropic Compression-Actual Temperature of Rammed Air)
Actual Coefficient of Performance = (210*Tonnage of Refrigeration in TR)/(Input Power*60)

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