Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load Calculator

✖Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit.ⓘ Peak Input Voltage SP [V_(max)]			+10% -10%
✖Resistance SP is a measure of the opposition to current flow in an electrical circuit. Its S.I unit is ohm.ⓘ Resistance SP [r]			+10% -10%
✖Diode Extinction Angle is the angle (in radians) beyond which a diode stops conduction and diode current falls to 0.ⓘ Diode Extinction Angle [β_diode]			+10% -10%

✖Average Output Current Half is the average of the dc value of the output current.ⓘ Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load [I_avg(h)]

⎘ Copy

👎

Formula

LaTeX

Reset

👍

Download Single Phase Uncontrolled Rectifiers Formulas PDF PDF Image

Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load Solution

STEP 0: Pre-Calculation Summary

Formula Used

Average Output Current Half = (Peak Input Voltage SP/(2*pi*Resistance SP))/(1-cos(Diode Extinction Angle))
I_avg(h) = (V_(max)/(2*pi*r))/(1-cos(β_diode))
This formula uses 1 Constants, 1 Functions, 4 Variables

Constants Used

pi - Archimedes' constant Value Taken As 3.14159265358979323846264338327950288

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)

Variables Used

Average Output Current Half - (Measured in Ampere) - Average Output Current Half is the average of the dc value of the output current.
Peak Input Voltage SP - (Measured in Volt) - Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit.
Resistance SP - (Measured in Ohm) - Resistance SP is a measure of the opposition to current flow in an electrical circuit. Its S.I unit is ohm.
Diode Extinction Angle - (Measured in Radian) - Diode Extinction Angle is the angle (in radians) beyond which a diode stops conduction and diode current falls to 0.

STEP 1: Convert Input(s) to Base Unit

Peak Input Voltage SP: 221 Volt --> 221 Volt No Conversion Required
Resistance SP: 59 Ohm --> 59 Ohm No Conversion Required
Diode Extinction Angle: 60 Radian --> 60 Radian No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

I_avg(h) = (V_(max)/(2*pi*r))/(1-cos(β_diode)) --> (221/(2*pi*59))/(1-cos(60))

Evaluating ... ...

I_avg(h) = 0.305343519646012

STEP 3: Convert Result to Output's Unit

0.305343519646012 Ampere --> No Conversion Required

FINAL ANSWER

0.305343519646012 ≈ 0.305344 Ampere <-- Average Output Current Half

(Calculation completed in 00.004 seconds)

You are here -

Home » Engineering » Electrical » Power Electronics » Uncontrolled Rectifiers » Single Phase Uncontrolled Rectifiers » Half Wave » Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load

Credits

Created by Parminder Singh

Chandigarh University (CU), Punjab

Parminder Singh has created this Calculator and 100+ more calculators!

Verified by Rachita C

BMS College Of Engineering (BMSCE), Banglore

Rachita C has verified this Calculator and 50+ more calculators!

< Half Wave Calculators

Average Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go Average Load Current SP = Peak Input Voltage SP/(pi*Resistance SP)

RMS Load Current of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go RMS Load Current SP = Peak Input Voltage SP/(2*Resistance SP)

Average Output Voltage of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go Average Output Voltage Half = Peak Input Voltage SP/pi

RMS Output Voltage of Single Phase Half Wave Diode Rectifier with Resistive Load

LaTeX Go RMS Output Voltage Half = Peak Input Voltage SP/2

Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load Formula

LaTeX Go

Average Output Current Half = (Peak Input Voltage SP/(2*pi*Resistance SP))/(1-cos(Diode Extinction Angle))
I_avg(h) = (V_(max)/(2*pi*r))/(1-cos(β_diode))

Why does the conduction continues till β?

At ωt = π, the load voltage Vo reduces to zero. However, the load current will not be zero at this instant because of inductance L. Due to this, diode will not turn off, even though it is reversed biased. Rather it will continue to conduct till ωt = β. At ωt = β, the load current becomes zero and didoe is reversed biased, hence it will turn off.

How to Calculate Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load?

Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load calculator uses Average Output Current Half = (Peak Input Voltage SP/(2*pi*Resistance SP))/(1-cos(Diode Extinction Angle)) to calculate the Average Output Current Half, The Average output current of single phase half wave diode rectifier with resistive and inductive load formula is defined as the average of current on the output side of a rectifier over a complete cycle when the load is resistive and inductive in nature. Average Output Current Half is denoted by I_avg(h) symbol.

How to calculate Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load using this online calculator? To use this online calculator for Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load, enter Peak Input Voltage SP (V_(max)), Resistance SP (r) & Diode Extinction Angle (β_diode) and hit the calculate button. Here is how the Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load calculation can be explained with given input values -> 0.305344 = (221/(2*pi*59))/(1-cos(60)).

FAQ

What is Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load?

The Average output current of single phase half wave diode rectifier with resistive and inductive load formula is defined as the average of current on the output side of a rectifier over a complete cycle when the load is resistive and inductive in nature and is represented as I_avg(h) = (V_(max)/(2*pi*r))/(1-cos(β_diode)) or Average Output Current Half = (Peak Input Voltage SP/(2*pi*Resistance SP))/(1-cos(Diode Extinction Angle)). Peak Input Voltage SP is the peak of the alternating voltage provided at the input of any electrical circuit, Resistance SP is a measure of the opposition to current flow in an electrical circuit. Its S.I unit is ohm & Diode Extinction Angle is the angle (in radians) beyond which a diode stops conduction and diode current falls to 0.

How to calculate Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load?

The Average output current of single phase half wave diode rectifier with resistive and inductive load formula is defined as the average of current on the output side of a rectifier over a complete cycle when the load is resistive and inductive in nature is calculated using Average Output Current Half = (Peak Input Voltage SP/(2*pi*Resistance SP))/(1-cos(Diode Extinction Angle)). To calculate Average Output Current of Single Phase Half Wave Diode Rectifier with Resistive and Inductive Load, you need Peak Input Voltage SP (V_(max)), Resistance SP (r) & Diode Extinction Angle (β_diode). With our tool, you need to enter the respective value for Peak Input Voltage SP, Resistance SP & Diode Extinction Angle and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Average Output Current Half?

In this formula, Average Output Current Half uses Peak Input Voltage SP, Resistance SP & Diode Extinction Angle. We can use 1 other way(s) to calculate the same, which is/are as follows -

Average Output Current Half = Peak Input Voltage SP/(pi*Resistance SP)

Home

FREE PDFs

🔍 Search