Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Current Underground AC is defined as the current flowing through the overhead ac supply wire.ⓘ Current Underground AC [I]			+10% -10%

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) [A]

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Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))
A = 2*ρ*L/(P_loss*(I^2))
This formula uses 5 Variables

Variables Used

Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Current Underground AC - (Measured in Ampere) - Current Underground AC is defined as the current flowing through the overhead ac supply wire.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Current Underground AC: 9 Ampere --> 9 Ampere No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

A = 2*ρ*L/(P_loss*(I^2)) --> 2*1.7E-05*24/(2.67*(9^2))

Evaluating ... ...

A = 3.77306145096407E-06

STEP 3: Convert Result to Output's Unit

3.77306145096407E-06 Square Meter --> No Conversion Required

FINAL ANSWER

3.77306145096407E-06 ≈ 3.8E-6 Square Meter <-- Area of Underground AC Wire

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length using Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Area of Underground AC Wire*Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2)/(4*(Power Transmitted^2)*Resistivity)

Area of X-Section (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))

Length using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Length of Underground AC Wire = Line Losses*Area of Underground AC Wire/(2*Resistivity*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)

LaTeX Go Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) Formula

LaTeX Go

Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2))
A = 2*ρ*L/(P_loss*(I^2))

What is the value of maximum voltage and volume of conductor material in this system?

The volume of conductor material required in this system is 2/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m so that r.m.s. value of voltage between them is v_m/√2.

How to Calculate Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) calculator uses Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2)) to calculate the Area of Underground AC Wire, The Area using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) using this online calculator? To use this online calculator for Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed), enter Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (P_loss) & Current Underground AC (I) and hit the calculate button. Here is how the Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed) calculation can be explained with given input values -> 3.8E-6 = 2*1.7E-05*24/(2.67*(9^2)).

FAQ

What is Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

The Area using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = 2*ρ*L/(P_loss*(I^2)) or Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2)). Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use & Current Underground AC is defined as the current flowing through the overhead ac supply wire.

How to calculate Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed)?

The Area using Line Losses (1-phase 2-wire Mid-point Earthed) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = 2*Resistivity*Length of Underground AC Wire/(Line Losses*(Current Underground AC^2)). To calculate Area using Line Losses (1-Phase 2-Wire Mid-Point Earthed), you need Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (P_loss) & Current Underground AC (I). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Line Losses & Current Underground AC and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Area of Underground AC Wire?

In this formula, Area of Underground AC Wire uses Resistivity, Length of Underground AC Wire, Line Losses & Current Underground AC. We can use 2 other way(s) to calculate the same, which is/are as follows -

Area of Underground AC Wire = 4*Resistivity*Length of Underground AC Wire*(Power Transmitted^2)/(Line Losses*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
Area of Underground AC Wire = Volume Of Conductor/(2*Length of Underground AC Wire)

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