Area of X-Section using Line Losses (2-Phase 3-Wire US) Calculator

✖Resistivity is the measure of how strongly a material opposes the flow of current through them.ⓘ Resistivity [ρ]			+10% -10%
✖Length of Underground AC Wire is the total length of the wire from one end to other end.ⓘ Length of Underground AC Wire [L]			+10% -10%
✖Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.ⓘ Power Transmitted [P]			+10% -10%
✖Line Losses is defined as the total losses occurring in an Underground AC line when in use.ⓘ Line Losses [P_loss]			+10% -10%
✖Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.ⓘ Maximum Voltage Underground AC [V_m]			+10% -10%
✖Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.ⓘ Phase Difference [Φ]			+10% -10%

✖Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.ⓘ Area of X-Section using Line Losses (2-Phase 3-Wire US) [A]

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Area of X-Section using Line Losses (2-Phase 3-Wire US) Solution

STEP 0: Pre-Calculation Summary

Formula Used

Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2)
A = (2+sqrt(2))*ρ*L*(P)^2/(P_loss*(V_m*cos(Φ))^2)
This formula uses 2 Functions, 7 Variables

Functions Used

cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)

Variables Used

Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

STEP 1: Convert Input(s) to Base Unit

Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Phase Difference: 30 Degree --> 0.5235987755982 Radian (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

A = (2+sqrt(2))*ρ*L*(P)^2/(P_loss*(V_m*cos(Φ))^2) --> (2+sqrt(2))*1.7E-05*24*(300)^2/(2.67*(230*cos(0.5235987755982))^2)

Evaluating ... ...

A = 0.00118349154304133

STEP 3: Convert Result to Output's Unit

0.00118349154304133 Square Meter --> No Conversion Required

FINAL ANSWER

0.00118349154304133 ≈ 0.001183 Square Meter <-- Area of Underground AC Wire

(Calculation completed in 00.004 seconds)

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< Wire Parameters Calculators

Length using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/(Resistivity*((2+sqrt(2))*Power Transmitted^2)))

Line Losses using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Line Losses = ((2+sqrt(2))*Power Transmitted)^2*Resistivity*(Length of Underground AC Wire)^2/((Maximum Voltage Underground AC*cos(Phase Difference))^2*Volume Of Conductor)

Area of X Section using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)

Constant using Volume of Conductor Material (2 Phase 3 Wire US)

LaTeX Go Constant Underground AC = Volume Of Conductor*((cos(Phase Difference))^2)/(2.914)

Area of X-Section using Line Losses (2-Phase 3-Wire US) Formula

LaTeX Go

What is the value of maximum voltage and volume of conductor material in 2-phase 3-wire system?

The volume of conductor material required in this system is 2.914/cos²θ times that of 2-wire d.c.system with the one conductor earthed. The maximum voltage between conductors is v_m/√2 so that r.m.s. value of voltage between them is v_m/2.

How to Calculate Area of X-Section using Line Losses (2-Phase 3-Wire US)?

Area of X-Section using Line Losses (2-Phase 3-Wire US) calculator uses Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2) to calculate the Area of Underground AC Wire, The Area of X-Section using Line Losses (2-Phase 3-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier. Area of Underground AC Wire is denoted by A symbol.

How to calculate Area of X-Section using Line Losses (2-Phase 3-Wire US) using this online calculator? To use this online calculator for Area of X-Section using Line Losses (2-Phase 3-Wire US), enter Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ) and hit the calculate button. Here is how the Area of X-Section using Line Losses (2-Phase 3-Wire US) calculation can be explained with given input values -> 0.001183 = (2+sqrt(2))*1.7E-05*24*(300)^2/(2.67*(230*cos(0.5235987755982))^2).

FAQ

What is Area of X-Section using Line Losses (2-Phase 3-Wire US)?

The Area of X-Section using Line Losses (2-Phase 3-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier and is represented as A = (2+sqrt(2))*ρ*L*(P)^2/(P_loss*(V_m*cos(Φ))^2) or Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2). Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Line Losses is defined as the total losses occurring in an Underground AC line when in use, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire & Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.

How to calculate Area of X-Section using Line Losses (2-Phase 3-Wire US)?

The Area of X-Section using Line Losses (2-Phase 3-Wire US) formula is defined as the cross-sectional area simply as the square of the wire's diameter in mils and calls that our area in units of “circular mils.” This makes number handling ever so much easier is calculated using Area of Underground AC Wire = (2+sqrt(2))*Resistivity*Length of Underground AC Wire*(Power Transmitted)^2/(Line Losses*(Maximum Voltage Underground AC*cos(Phase Difference))^2). To calculate Area of X-Section using Line Losses (2-Phase 3-Wire US), you need Resistivity (ρ), Length of Underground AC Wire (L), Power Transmitted (P), Line Losses (P_loss), Maximum Voltage Underground AC (V_m) & Phase Difference (Φ). With our tool, you need to enter the respective value for Resistivity, Length of Underground AC Wire, Power Transmitted, Line Losses, Maximum Voltage Underground AC & Phase Difference and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Area of Underground AC Wire?

In this formula, Area of Underground AC Wire uses Resistivity, Length of Underground AC Wire, Power Transmitted, Line Losses, Maximum Voltage Underground AC & Phase Difference. We can use 2 other way(s) to calculate the same, which is/are as follows -

Area of Underground AC Wire = Volume Of Conductor/((2+sqrt(2))*Length of Underground AC Wire)
Area of Underground AC Wire = Resistivity*Length of Underground AC Wire/(sqrt(2)*Resistance Underground AC)

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