Angle using Area of X Section (1 Phase 3 Wire US) Solution

STEP 0: Pre-Calculation Summary
Formula Used
Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))
Φ = acos((2*P/Vm)*sqrt(ρ*L/(Ploss*A)))
This formula uses 3 Functions, 7 Variables
Functions Used
cos - Cosine of an angle is the ratio of the side adjacent to the angle to the hypotenuse of the triangle., cos(Angle)
acos - The inverse cosine function, is the inverse function of the cosine function. It is the function that takes a ratio as an input and returns the angle whose cosine is equal to that ratio., acos(Number)
sqrt - A square root function is a function that takes a non-negative number as an input and returns the square root of the given input number., sqrt(Number)
Variables Used
Phase Difference - (Measured in Radian) - Phase Difference is defined as the difference between the phasor of apparent and real power (in degrees) or between voltage and current in an ac circuit.
Power Transmitted - (Measured in Watt) - Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work.
Maximum Voltage Underground AC - (Measured in Volt) - Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire.
Resistivity - (Measured in Ohm Meter) - Resistivity is the measure of how strongly a material opposes the flow of current through them.
Length of Underground AC Wire - (Measured in Meter) - Length of Underground AC Wire is the total length of the wire from one end to other end.
Line Losses - (Measured in Watt) - Line Losses is defined as the total losses occurring in an Underground AC line when in use.
Area of Underground AC Wire - (Measured in Square Meter) - Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
STEP 1: Convert Input(s) to Base Unit
Power Transmitted: 300 Watt --> 300 Watt No Conversion Required
Maximum Voltage Underground AC: 230 Volt --> 230 Volt No Conversion Required
Resistivity: 1.7E-05 Ohm Meter --> 1.7E-05 Ohm Meter No Conversion Required
Length of Underground AC Wire: 24 Meter --> 24 Meter No Conversion Required
Line Losses: 2.67 Watt --> 2.67 Watt No Conversion Required
Area of Underground AC Wire: 1.28 Square Meter --> 1.28 Square Meter No Conversion Required
STEP 2: Evaluate Formula
Substituting Input Values in Formula
Φ = acos((2*P/Vm)*sqrt(ρ*L/(Ploss*A))) --> acos((2*300/230)*sqrt(1.7E-05*24/(2.67*1.28)))
Evaluating ... ...
Φ = 1.54228931446658
STEP 3: Convert Result to Output's Unit
1.54228931446658 Radian -->88.3666685070769 Degree (Check conversion ​here)
FINAL ANSWER
88.3666685070769 88.36667 Degree <-- Phase Difference
(Calculation completed in 00.004 seconds)

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Wire Parameters Calculators

Angle of PF using Volume of Conductor Material(1 Phase 3 Wire US)
​ LaTeX ​ Go Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))
Length using Volume of Conductor Material(1 Phase 3 Wire US)
​ LaTeX ​ Go Length of Underground AC Wire = sqrt(Volume Of Conductor*Line Losses*(cos(Phase Difference)*Maximum Voltage Underground AC)^2/((10)*Resistivity*(Power Transmitted^2)))
Line Losses using Volume of Conductor Material(1 Phase 3 Wire US)
​ LaTeX ​ Go Line Losses = 10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Volume Of Conductor*((Maximum Voltage Underground AC*cos(Phase Difference))^2))
Constant using Volume of Conductor Material(1 Phase 3 Wire US)
​ LaTeX ​ Go Constant Underground AC = Volume Of Conductor*(cos(Phase Difference)^2)/(2.5)

Angle using Area of X Section (1 Phase 3 Wire US) Formula

​LaTeX ​Go
Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire)))
Φ = acos((2*P/Vm)*sqrt(ρ*L/(Ploss*A)))

How do you calculate power factor?

Power factor (PF) is the ratio of working power, measured in kilowatts (kW), to apparent power, measured in kilovolt amperes (kVA). Apparent power, also known as demand, is the measure of the amount of power used to run machinery and equipment during a certain period. It is found by multiplying (kVA = V x A).

How to Calculate Angle using Area of X Section (1 Phase 3 Wire US)?

Angle using Area of X Section (1 Phase 3 Wire US) calculator uses Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))) to calculate the Phase Difference, The Angle using Area Of X section (1 phase 3 wire US) formula is defined as the phase angle between reactive and active power. Phase Difference is denoted by Φ symbol.

How to calculate Angle using Area of X Section (1 Phase 3 Wire US) using this online calculator? To use this online calculator for Angle using Area of X Section (1 Phase 3 Wire US), enter Power Transmitted (P), Maximum Voltage Underground AC (Vm), Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (Ploss) & Area of Underground AC Wire (A) and hit the calculate button. Here is how the Angle using Area of X Section (1 Phase 3 Wire US) calculation can be explained with given input values -> 5063.037 = acos((2*300/230)*sqrt(1.7E-05*24/(2.67*1.28))).

FAQ

What is Angle using Area of X Section (1 Phase 3 Wire US)?
The Angle using Area Of X section (1 phase 3 wire US) formula is defined as the phase angle between reactive and active power and is represented as Φ = acos((2*P/Vm)*sqrt(ρ*L/(Ploss*A))) or Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))). Power Transmitted is the amount of power that is transferred from its place of generation to a location where it is applied to perform useful work, Maximum Voltage Underground AC is defined as the peak amplitude of the AC voltage supplied to the line or wire, Resistivity is the measure of how strongly a material opposes the flow of current through them, Length of Underground AC Wire is the total length of the wire from one end to other end, Line Losses is defined as the total losses occurring in an Underground AC line when in use & Area of Underground AC Wire is defined as the cross-sectional area of the wire of an AC supply system.
How to calculate Angle using Area of X Section (1 Phase 3 Wire US)?
The Angle using Area Of X section (1 phase 3 wire US) formula is defined as the phase angle between reactive and active power is calculated using Phase Difference = acos((2*Power Transmitted/Maximum Voltage Underground AC)*sqrt(Resistivity*Length of Underground AC Wire/(Line Losses*Area of Underground AC Wire))). To calculate Angle using Area of X Section (1 Phase 3 Wire US), you need Power Transmitted (P), Maximum Voltage Underground AC (Vm), Resistivity (ρ), Length of Underground AC Wire (L), Line Losses (Ploss) & Area of Underground AC Wire (A). With our tool, you need to enter the respective value for Power Transmitted, Maximum Voltage Underground AC, Resistivity, Length of Underground AC Wire, Line Losses & Area of Underground AC Wire and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.
How many ways are there to calculate Phase Difference?
In this formula, Phase Difference uses Power Transmitted, Maximum Voltage Underground AC, Resistivity, Length of Underground AC Wire, Line Losses & Area of Underground AC Wire. We can use 1 other way(s) to calculate the same, which is/are as follows -
  • Phase Difference = acos(sqrt(10*Resistivity*((Power Transmitted*Length of Underground AC Wire)^2)/(Line Losses*Volume Of Conductor*((Maximum Voltage Underground AC)^2))))
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