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Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time Calculator

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✖Depression Head in Well 1 is the depression head in the well when pumping stopped.ⓘ Depression Head in Well 1 [h_w1]			+10% -10%
✖Discharge in Well is the rate of flow of a liquid in well.ⓘ Discharge in Well [Q]			+10% -10%
✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time [t]			+10% -10%
✖Cross-Sectional Area of Well is the the surface area of the interior opening of the well.ⓘ Cross-Sectional Area of Well [A_csw]			+10% -10%
✖Constant Depression Head is the constant value of head in the well.ⓘ Constant Depression Head [H']			+10% -10%

✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time [h_w2]

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Formula

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Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time

Formula

h w2 = \frac{h w1}{10^{\frac{Q \cdot \frac{t}{3600}}{A csw \cdot H' \cdot 2.303}}}

Example

0.000992 m = \frac{3 m}{10^{\frac{0.99 m³/s \cdot \frac{4 h}{3600}}{13 m² \cdot 0.038 \cdot 2.303}}}

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Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time Solution

STEP 0: Pre-Calculation Summary

Formula Used

Depression Head in Well 2 = Depression Head in Well 1/(10^((Discharge in Well*Time/3600)/(Cross-Sectional Area of Well*Constant Depression Head*2.303)))
h_w2 = h_w1/(10^((Q*t/3600)/(A_csw*H'*2.303)))
This formula uses 6 Variables

Variables Used

Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Depression Head in Well 1 - (Measured in Meter) - Depression Head in Well 1 is the depression head in the well when pumping stopped.
Discharge in Well - (Measured in Cubic Meter per Second) - Discharge in Well is the rate of flow of a liquid in well.
Time - (Measured in Second) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.
Cross-Sectional Area of Well - (Measured in Square Meter) - Cross-Sectional Area of Well is the the surface area of the interior opening of the well.
Constant Depression Head - Constant Depression Head is the constant value of head in the well.

STEP 1: Convert Input(s) to Base Unit

Depression Head in Well 1: 3 Meter --> 3 Meter No Conversion Required
Discharge in Well: 0.99 Cubic Meter per Second --> 0.99 Cubic Meter per Second No Conversion Required
Time: 4 Hour --> 14400 Second (Check conversion here)
Cross-Sectional Area of Well: 13 Square Meter --> 13 Square Meter No Conversion Required
Constant Depression Head: 0.038 --> No Conversion Required

STEP 2: Evaluate Formula

Substituting Input Values in Formula

h_w2 = h_w1/(10^((Q*t/3600)/(A_csw*H'*2.303))) --> 3/(10^((0.99*14400/3600)/(13*0.038*2.303)))

Evaluating ... ...

h_w2 = 0.000991652463897238

STEP 3: Convert Result to Output's Unit

0.000991652463897238 Meter --> No Conversion Required

FINAL ANSWER

0.000991652463897238 ≈ 0.000992 Meter <-- Depression Head in Well 2

(Calculation completed in 00.004 seconds)

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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Meerut Institute of Engineering and Technology (MIET), Meerut

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< Depression Head after Pumping Stopped Calculators

Depression Head in Well at Time T after Pumping Stopped

Go Depression Head = Depression Head in Well/exp(Specific Capacity*Time)

Depression Head in Well at Time T after Pumping Stopped with Base 10

Go Depression Head in Well 2 = Depression Head in Well 1/10^((Specific Capacity*Time)/2.303)

Depression Head in Well at Time T after Pumping Stopped with Base 10 and Clay soil is Present

Go Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600)/2.303)

Depression Head in Well at Time T after Pumping Stopped and Clay Soil is Present

Go Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600))

Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time Formula

Depression Head in Well 2 = Depression Head in Well 1/(10^((Discharge in Well*Time/3600)/(Cross-Sectional Area of Well*Constant Depression Head*2.303)))
h_w2 = h_w1/(10^((Q*t/3600)/(A_csw*H'*2.303)))

What is Discharge?

Discharge in the context of wells, rivers, or any hydraulic system refers to the volume of water flowing out of a particular source over a given period of time. It’s often used to describe the amount of water being produced or released from a well, river, or drainage system. Discharge is a critical factor in evaluating the capacity of a well or river to provide water. For example, higher discharge rates in a well indicate higher water yield, which is important for assessing its productivity and sustainability.

How to Calculate Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time?

Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time calculator uses Depression Head in Well 2 = Depression Head in Well 1/(10^((Discharge in Well*Time/3600)/(Cross-Sectional Area of Well*Constant Depression Head*2.303))) to calculate the Depression Head in Well 2, Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time calculates value of depression head when we have prior information of other parameters used. Depression Head in Well 2 is denoted by h_w2 symbol.

How to calculate Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time using this online calculator? To use this online calculator for Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time, enter Depression Head in Well 1 (h_w1), Discharge in Well (Q), Time (t), Cross-Sectional Area of Well (A_csw) & Constant Depression Head (H') and hit the calculate button. Here is how the Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time calculation can be explained with given input values -> 0.000843 = 3/(10^((0.99*14400/3600)/(13*0.038*2.303))).

FAQ

What is Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time?

Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time calculates value of depression head when we have prior information of other parameters used and is represented as h_w2 = h_w1/(10^((Q*t/3600)/(A_csw*H'*2.303))) or Depression Head in Well 2 = Depression Head in Well 1/(10^((Discharge in Well*Time/3600)/(Cross-Sectional Area of Well*Constant Depression Head*2.303))). Depression Head in Well 1 is the depression head in the well when pumping stopped, Discharge in Well is the rate of flow of a liquid in well, Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future, Cross-Sectional Area of Well is the the surface area of the interior opening of the well & Constant Depression Head is the constant value of head in the well.

How to calculate Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time?

Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time calculates value of depression head when we have prior information of other parameters used is calculated using Depression Head in Well 2 = Depression Head in Well 1/(10^((Discharge in Well*Time/3600)/(Cross-Sectional Area of Well*Constant Depression Head*2.303))). To calculate Depression Head in Well at Time T after Pumping Stopped with known Discharge and Time, you need Depression Head in Well 1 (h_w1), Discharge in Well (Q), Time (t), Cross-Sectional Area of Well (A_csw) & Constant Depression Head (H'). With our tool, you need to enter the respective value for Depression Head in Well 1, Discharge in Well, Time, Cross-Sectional Area of Well & Constant Depression Head and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Depression Head in Well 2?

In this formula, Depression Head in Well 2 uses Depression Head in Well 1, Discharge in Well, Time, Cross-Sectional Area of Well & Constant Depression Head. We can use 3 other way(s) to calculate the same, which is/are as follows -

Depression Head in Well 2 = Depression Head in Well 1/10^((Specific Capacity*Time)/2.303)
Depression Head in Well 2 = (Depression Head in Well 1/10^((1/2.303)*(Time/3600)))
Depression Head in Well 2 = Depression Head in Well 1/10^((1*Time/3600)/2.303)

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