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Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand Calculator

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✖Depression Head in Well 1 is the depression head in the well when pumping stopped.ⓘ Depression Head in Well 1 [h_w1]			+10% -10%
✖Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.ⓘ Time [t]			+10% -10%

✖Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.ⓘ Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand [h_w2]

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Formula

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Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand

Formula

h w2 = \frac{h w1}{10^{\frac{1 \cdot \frac{t}{3600}}{2.303}}}

Example

0.054987 m = \frac{3 m}{10^{\frac{1 \cdot \frac{4 h}{3600}}{2.303}}}

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Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand Solution

STEP 0: Pre-Calculation Summary

Formula Used

Depression Head in Well 2 = Depression Head in Well 1/10^((1*Time/3600)/2.303)
h_w2 = h_w1/10^((1*t/3600)/2.303)
This formula uses 3 Variables

Variables Used

Depression Head in Well 2 - (Measured in Meter) - Depression Head in Well 2 is depression head in the well at a time T after the pumping stopped.
Depression Head in Well 1 - (Measured in Meter) - Depression Head in Well 1 is the depression head in the well when pumping stopped.
Time - (Measured in Second) - Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.

STEP 1: Convert Input(s) to Base Unit

Depression Head in Well 1: 3 Meter --> 3 Meter No Conversion Required
Time: 4 Hour --> 14400 Second (Check conversion here)

STEP 2: Evaluate Formula

Substituting Input Values in Formula

h_w2 = h_w1/10^((1*t/3600)/2.303) --> 3/10^((1*14400/3600)/2.303)

Evaluating ... ...

h_w2 = 0.0549865277424508

STEP 3: Convert Result to Output's Unit

0.0549865277424508 Meter --> No Conversion Required

FINAL ANSWER

0.0549865277424508 ≈ 0.054987 Meter <-- Depression Head in Well 2

(Calculation completed in 00.004 seconds)

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Created by Suraj Kumar

Birsa Institute of Technology (BIT), Sindri

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Meerut Institute of Engineering and Technology (MIET), Meerut

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< Depression Head after Pumping Stopped Calculators

Depression Head in Well at Time T after Pumping Stopped

Go Depression Head = Depression Head in Well/exp(Specific Capacity*Time)

Depression Head in Well at Time T after Pumping Stopped with Base 10

Go Depression Head in Well 2 = Depression Head in Well 1/10^((Specific Capacity*Time)/2.303)

Depression Head in Well at Time T after Pumping Stopped with Base 10 and Clay soil is Present

Go Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600)/2.303)

Depression Head in Well at Time T after Pumping Stopped and Clay Soil is Present

Go Depression Head after Pumping Stopped = Depression Head in Well 1/10^((0.25*Time/3600))

Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand Formula

Depression Head in Well 2 = Depression Head in Well 1/10^((1*Time/3600)/2.303)
h_w2 = h_w1/10^((1*t/3600)/2.303)

What is Coarse Soil?

Coarse soil refers to soil particles that are larger in size and typically include gravel, sand, and silt. This type of soil has distinct characteristics that influence its physical properties, drainage capabilities, and suitability for various construction and agricultural applications. Coarse soil is often classified based on particle size and texture.

How to Calculate Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand?

Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand calculator uses Depression Head in Well 2 = Depression Head in Well 1/10^((1*Time/3600)/2.303) to calculate the Depression Head in Well 2, Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand calculates value of depression head when we have prior information of other parameters used. Depression Head in Well 2 is denoted by h_w2 symbol.

How to calculate Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand using this online calculator? To use this online calculator for Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand, enter Depression Head in Well 1 (h_w1) & Time (t) and hit the calculate button. Here is how the Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand calculation can be explained with given input values -> 0.054987 = 3/10^((1*14400/3600)/2.303).

FAQ

What is Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand?

Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand calculates value of depression head when we have prior information of other parameters used and is represented as h_w2 = h_w1/10^((1*t/3600)/2.303) or Depression Head in Well 2 = Depression Head in Well 1/10^((1*Time/3600)/2.303). Depression Head in Well 1 is the depression head in the well when pumping stopped & Time refers to the ongoing and continuous sequence of events that occur in succession, from the past through the present to the future.

How to calculate Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand?

Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand calculates value of depression head when we have prior information of other parameters used is calculated using Depression Head in Well 2 = Depression Head in Well 1/10^((1*Time/3600)/2.303). To calculate Depression Head in Well at Time T after Pumping Stopped with Base 10 in Coarse Sand, you need Depression Head in Well 1 (h_w1) & Time (t). With our tool, you need to enter the respective value for Depression Head in Well 1 & Time and hit the calculate button. You can also select the units (if any) for Input(s) and the Output as well.

How many ways are there to calculate Depression Head in Well 2?

In this formula, Depression Head in Well 2 uses Depression Head in Well 1 & Time. We can use 3 other way(s) to calculate the same, which is/are as follows -

Depression Head in Well 2 = Depression Head in Well 1/10^((Specific Capacity*Time)/2.303)
Depression Head in Well 2 = (Depression Head in Well 1/10^((1/2.303)*(Time/3600)))
Depression Head in Well 2 = Depression Head in Well 1/(10^((Discharge in Well*Time/3600)/(Cross-Sectional Area of Well*Constant Depression Head*2.303)))

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